Wii VC Round-to-Zero: Difference between revisions

I updated the info on platform rising across a boundary to really be in terms of velocity and position. Also, it's hard to say "the platform accelerates back to its initial acceleration" because the initial acceleration is fucking infinity for an infi...
m (Added Wii VC inaccuracy to Category:Glitches)
(I updated the info on platform rising across a boundary to really be in terms of velocity and position. Also, it's hard to say "the platform accelerates back to its initial acceleration" because the initial acceleration is fucking infinity for an infi...)
Tags: Mobile edit Mobile web edit
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Once it passes y=-2048, the platform halves in rising speed: ~6.5403cm/h. The platform continues to halve in speed as it passes through y=-1024, y=-512, y=-256, and all other 2^n boundaries til it comes to a halt near y=0.
Once it passes y=-2048, the platform halves in rising speed: ~6.5403cm/h. The platform continues to halve in speed as it passes through y=-1024, y=-512, y=-256, and all other 2^n boundaries til it comes to a halt near y=0.


As it passes through a 2^n boundary, its behavior becomes complex. Throughout its up-down oscillation cycle, the platform is sometimes past the 2^n boundary and sometimes not. The overall speed decrease as the platform's average height passes through the 2^n boundary is represented by a arctangent function: the platform suddenly slows down, then decelerates before it accelerates back to its initial acceleration again, before completely stopping at a constant speed.
As it passes through a 2^n boundary, its behavior becomes complex. Throughout its up-down oscillation cycle, the platform is sometimes past the 2^n boundary and sometimes not. The overall speed decrease as the platform's average height passes through the 2^n boundary is represented by a differential equation of velocity=dx/dt=arccos(x): the platform suddenly slows down, then decelerates before it accelerates back, and suddenly completely stopping at a constant speed half of what it started with.


The platforms at the beginning of the level are below ''y'' = 0, and so they gradually rise upward. Over the course of several days, they are high enough they can be used to reach the elevator past the pole, which previously required one A press to get past. It takes eight days for the platform to reach high enough for a dive recover to land in the elevator shaft, but using [[Vertical Speed Conservation|VSC]] with a lava boost requires only three days.
The platforms at the beginning of the level are below ''y'' = 0, and so they gradually rise upward. Over the course of several days, they are high enough they can be used to reach the elevator past the pole, which previously required one A press to get past. It takes eight days for the platform to reach high enough for a dive recover to land in the elevator shaft, but using [[Vertical Speed Conservation|VSC]] with a lava boost requires only three days.
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