Iwerlipse: Difference between revisions

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The problem was posed by jongyon7192p as a curiosity, and it became relevant to the ABC challenge a few times before being solved through some other means.
The problem was posed by DeRockProject as a curiosity, and it became relevant to the ABC challenge a few times before being solved through some other means.


Iwer stated on April 2018 that optimal straining for the Air_no_Turn action is <math>\text{dyaw}(t,r) = \text{acotan}(0.15r*t) </math>.  
Iwer stated on April 2018 that optimal straining for the Air_no_Turn action is <math>\text{dyaw}(t,r) = \text{acotan}(0.15r*t) </math>.  


On October 2019, trex31415 provided a full analytical proof for Iwer's claim, using a generalized 2nd-order Euler-Lagrange equation.
On October 2019, Silverstrawb provided a full analytical proof for Iwer's claim, using a generalized 2nd-order Euler-Lagrange equation.




By plugging Iwer and Trex's equation to solve for x and y, we obtain the parametric equations, the solution to the Iwerlipse after <math>n</math> frames:
 
By plugging Iwer and Silverstrawb's equation to solve for x and y, we obtain the parametric equations, the solution to the Iwerlipse after <math>n</math> frames:


<math>x(n,t) = \pm \frac{v_xnt}{\sinh(t)} </math>
<math>x(n,t) = \pm \frac{v_xnt}{\sinh(t)} </math>
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